$1 yard (yd) = 3 feet (ft)$
$1 yard (yd) =36 inches (in)$
$1 mile (mi) = 5,280 feet (ft)$
Units of Mass in English System | Units of Mass in the Metric System | System to System Conversions for Mass |
---|---|---|
$1 ounces (oz) = 437.5 grains $ $ 1 pound (lb) = 16 ounces (oz)$ $ 1 ton (T) = 2, 000 lb$ | $1 gram (g) = 1, 000 milligram (mg)$ $1 gram (g) = 100 centigram (cg)$ $1 kilogram (kg)= 1000 grams (g)$ $1 metric ton (t) = 1, 000 kg$ | $1 oz ≈ 28.3 g$ $1 lb ≈0.45 kg$ |
Units of Area in English System | Units of Area in the Metric System | System to System Conversions for Mass |
---|---|---|
$1 {ft^2} = 144 in^2$ $1 {yd^2} = 9 {ft^2}$ $1 acre = 43, 560 ft^2$ $1 {mi^2} = 640 acres$ | $1 cm^2 = 100 {mm^2}$ $1 {dm^2} = 100 {cm^2}$ $1 {m^2} = 100 {dm^2}$ $1 are (a) = 100 {m^2}$ $1 hectare (ha) = 100 a$ $100 hectares (ha) = 1 {km^2}$ | $1 in^2 ≈ 6.45 {cm^2}$ $1 m^2 ≈ 1.196 {yd^2}$ $1 ha ≈ 2.47 acres$ |
Units of Volume in English System | Units of Volume in the Metric System | System to System Conversions for Volume |
---|---|---|
$1 ft^3 = 1, 728 in^3$ $1 yd^3 = 27 ft^3$ $1 cord = 128 ft^3$ | $1 cc = 1 cm^3$ $1 mL = 1 cm^3$ $1 L = 1, 000 mL$ $1 hL = 100 L$ $1 kL = 1, 000 L$ | $1 in^3 ≈ 16.39 mL$ $1 liter ≈ 1.06 qt$ $1 gallon ≈ 3.79 liters$ $1 m3 ≈ 35.31 ft^3$ $1 quart ≈ 0.95 L$ |
Units of Fluid Volume in English System | Units of Time in the Both System | System to System Conversions for Temperature |
---|---|---|
$1 tablespoon (T) = 3 teaspoons (tsp)$ $1 fluid ounce (fl oz) = 2T 1$ $cup (c) = 8 fl oz$ $1 pint (pt) = 2 c$ $1 quart (qt) = 2 pt$ $1 gallon (gal) = 4 qt$ $1 gal = 128 fl oz 1$ $barrel = 42 gallon$ | $1 millisecond=1000 microseconds$ $1 second = 1000 millisecond$ $1 minute = 60 seconds$ $1 hour = 60 minutes$ $1 day ≈ 24 hours (hrs)$ $1 month ≈ 30 days$ $1 year ≈ 365 days$ $1 banking year = 360 days$ $1 decade = 10 years$ $1 score = 20 years$ $1 millennium = 1, 000 years$ | $°F \to °C$ $°C = {5 \over 9} (°F – 32)$ $°C \to °F$ $°F = {9 \over 5}°C + 32$ $°K \to °C$ $°K = °C + 273$ |
Giga (G) | Mega (M) | Kilo (k) | Hecto (h) | Deka (da, D) | Gram(g) Meter(m) Liter(L) | Deci (d) | Centi (c) | Milli (m) | Micro (μ) | Nano (n) |
---|---|---|---|---|---|---|---|---|---|---|
$10^9$ | $10^6$ | $10^3$ | $10^2$ | $10^1$ | $1$ | $10^{-1}$ | $10^{-2}$ | $10^{-3}$ | $10^{-6}$ | $10^{-9}$ |
1. Compare the two units.
2. Find the conversion factors that gives the appropriate ratio to the given unit.
3. Write the conversion as a fraction, where the denominator is in the same unit as the given unit.
4. Write a multiplication problem with the original number and the fraction.
5. Cancel out similar units that appears on the numerator and denominator.
Convert mass, convert area, convert volume, convert time, try this unit conversion calculator.
This unit converter is a free and easy to use tool for converting units of measurements.
It converts length, area, volume, weight, speed, density and temperature. It also converts between different units of measurement.
The converter is available in metric or imperial units. You can type in the unit you want to convert into the search bar or click on the links below to find your desired unit.
When changing from one unit of measurement to another, it is very important to know the table of conversion because this will be your guide.
There are some measurements in the table that can't be changed directly, so we should know which conversion factor is the easiest to use.
You need to know and be good at converting units before you can use the different problem-solving strategies to solve problems that involve converting units.
Unit conversions are a necessary skill in the workplace. Whether you are a student, engineer, or an accountant, you will need to know how to convert units of measurement.
Use these tips to succeed at unit conversions with ease:
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Conversions | ||||||
---|---|---|---|---|---|---|
kilometer meters | minute seconds | liter milliliters | ||||
meter centimeter | hour minutes | kilogram grams | ||||
meter millimeters | gram milligrams | |||||
centimeter millimeters |
Unit conversion problems constitute the first week of nearly every science course. Measurement is a basic skill in science, but not all measurement methods are the same. People measure the same thing in different ways and use different units. To communicate between scientists, there has to be a method of converting between the different measurement units.
This is a collection of unit conversion example problems to help you learn the general method and mindset of converting units. Most of these include an example going the opposite direction (for example: cm to m and m to cm).
Use the ladder method or dimensional analysis to tackle conversions between units. See how to use a conversion factor to step-by-step reach the desired end units. This method is especially useful for measurements with more than one conversion like kilometers/hour to meters/sec. The L/min to m3/hr Conversion Example is a conversion example which uses the Ladder Method.
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Word Problems on Conversion of Units : Conversion of units is a multi-step process that involves multiplication or division by a numerical factor. In Mathematics, while solving numerical problems, it is required to convert the units. Thus the conversion of units should be needed to solve the required calculations wherever it is necessary.
For example, if we need to calculate the area of the rectangle, in which length is given in centimetres \(\left( {{\rm{cm}}} \right)\), and the width is given in metres \({\rm{m}}\), then it is necessary to convert any one unit either length or width, so that both the units become the same.
Therefore, to solve the word problems in mathematics, learning the conversion of units is necessary. This article will discuss the conversion of units in more detail.
Conversion of units is a multi-step process that involves multiplication or division by a numerical factor. Word problems on the conversion of units consist of a few sentences describing a real-life scenario where mathematical definitions and concepts of converting units from one unit to another unit are used to solve a problem.
The conversion of units may also require selecting the correct number of significant digits and rounding off. In mathematics, we convert the units from one unit to the other unit for better understanding.
For example, the length of a garden is measured in yards, whereas the length of a table is measured in inches. But we cannot measure the length of a finger in miles. To measure different quantities, different units of measurements are needed.
The conversion of units should be needed to solve the required calculations wherever it is necessary. For example, if we need to calculate the area of the rectangle, in which length is given in centimetres \(\left( {{\rm{cm}}} \right)\), and the width is given in metres \(\left( {{\rm{m}}} \right)\), then it is necessary to convert any one unit, either length or width, to make them uniform.
In mathematics, we have metric systems such as measuring units of length and distance, weight, and capacity. As we discussed, to solve the word problems correctly, we need to learn the conversion of units, and it is necessary too.
The metric system was introduced in France in the year \(1790\). The metric system of measuring units is based on the decimal system. The base units for length is metre, for weight kilogram and seconds for the time.
Unit conversion is a multi-step process that involves multiplication or division by a numerical factor. To convert any bigger unit to a smaller unit, we should multiply with the conversion factor. Similarly, to convert any smaller unit to a bigger unit, we should divide it with the conversion factor.
Length is a one-dimensional scalar quantity, which measures the line segment. The basic unit used for measuring the length is a metre \({\rm{(m)}}\). Depending on the specimen or object used for measurement, we have different types of units like \({\rm{cm,}}\,{\rm{km,}}\,{\rm{inches,}}\,{\rm{ft}}\), etc.
For example, the length of a garden is measured in yards, whereas the length of a table is measured in inches. But we cannot measure the length of a finger in miles. To measure different quantities, different units of measurements are needed.
The below chart gives the conversion of length:
To convert a unit from a metre to a centimetre, we should multiply by \(100\) such that \(1\,{\rm{m}}\, = \,100\,{\rm{cm}}\)
Asit and Keerthi each ran on a treadmill exactly for \(90\) minutes. Asit’s treadmill showed he had run \(18500\) meters. Keerthi’s treadmill showed she had run \(20\) kilometres. Who ran farther, and how much?
The time took by the Keerthi and Asit are the same, that is \(90\) minutes.
Here, the distance covered by Asit and Keerthi has different measuring units. For uniformity in the calculation, we have to convert the units from \({\rm{km}}\) to \({\rm{m}}\) or \({\rm{m}}\) to \({\rm{km}}\).
Let us convert \({\rm{km}}\,\) to \({\rm{m}}\,\).
So, the distance covered by the Asit on the treadmill \( = 18,500\,{\rm{m}}\)
And, the distance covered by the Keerthi on treadmill \( = 20\,\,{\rm{km}}{\rm{ = }}{\rm{20}} \times {\rm{1000}}{\rm{m = }}{\rm{20,}}\,{\rm{000}}\,{\rm{m}}\)
The difference in their distances is \({\rm{20,}}\,{\rm{000}}\,{\rm{m}}\,{\rm{ – }}\,{\rm{18500}}\,{\rm{m}}\,{\rm{ = 1500}}\,{\rm{m}}\)
So, Keerthi ran farther as compared with Asit by \({\rm{20,}}\,{\rm{000}}\,{\rm{m}}\,{\rm{ – }}\,{\rm{18500}}\,{\rm{m}}\,{\rm{ = 1500}}\,{\rm{m}}\)
So, Keerthi ran farther as compared with Asit by \({\rm{1500}}\,{\rm{m}}\) or \({\rm{1.5}}\,{\rm{km}}\).
Weight is the one-dimensional vector quantity, which is used for the measurement of objects. Generally, the weight of the object is measured in the base unit kilogram \(\left( {{\rm{kg}}} \right).\) We know that weight of the person is measured in \({\rm{(kg)}}\) and the weight of the small pieces of gold is measured in grams. So, it is important to convert the units of the weights while solving word problems for uniformity in the calculation.
The below figure shows the conversion of weights from one unit to another unit:
Nag is carrying \(2.5\,{\rm{kg}}\) of apples and \(5\,{\rm{g}}\) of carrying bag. Find the total weight she is holding in her hand.
The total weight \( = 2.5 \times 1000\,{\rm{g}}\,{\rm{ + 5g}}\,{\rm{ = }}\,{\rm{2505}}\,{\rm{g}}\)
We know that seconds are the basic unit for measuring time. We have to convert the units of time from one unit to another unit for solving the problems. The below chart gives the conversion of time:
Example: The time taken to reach the shop is \(30\) minutes and from the due to heavy traffic, the time taken to reach the house is \(1\) hour. Find the total time taken?
The total time taken \( = 30\min {\rm{utes}} + 1 \times 60\min {\rm{utes}} = 90\min {\rm{utes}}\,\)
The area is the two-dimensional property. We have different units for measuring the area. The below figure shows the conversion of area units:
The area of the parking lot is \(12{{\rm{m}}^2}\) and \(50\,{\rm{c}}{{\rm{m}}^{\rm{2}}}\) Find the total area?
The total area \( = \,12\, \times \,{100^2}\,{\rm{c}}{{\rm{m}}^2}\, + \,500\,{\rm{c}}{{\rm{m}}^2}\, = \,1440000\, + 500\, = \,1440500\,{\rm{c}}{{\rm{m}}^2}\)
Capacity describes the volume of the object. The different types of units used for measuring the capacity are given below:
The capacity of the water bottle is \(1\,{\rm{l}}\) and the cap is \(1\,{\rm{ml}}\) Find the total capacity of the bottle.
The total capacity \( = 1 \times 1000\,{\rm{ml}} + 1\,{\rm{ml}} = 1001\,{\rm{ml}}\)
Q.1. The distance between the two places in a city is \(31,\,680\, feet\) Express the distance in miles. Ans: Given the distance between the places \({\rm{ = 31,680}}\,{\rm{feet}}\) We know that \({\rm{1feet}} = \frac{1}{{5280}}{\rm{miles}}\) So, total distance in miles \( = \frac{{31,680}}{{5280}} = 6\,{\rm{miles}}\)
Q.2. Asit’s mom took \(30\) minutes to cut the vegetables, and she took \(1\) hour in cooking. Find how many minutes she took to complete the whole cooking? Ans: The time taken for cutting the vegetables \( = 30\,{\rm{minutes}}\) The time taken for cooking \( = 1\,{\rm{hour}} = 60\,{\rm{minutes}}\) Total time taken for whole cooking \( = \,30\, + \,60\, = \,90\,{\rm{minutes}}\)
Q.3. Vicky has \(14,500\,{\rm{g}}\) of sand in his sandbox, and he bought \(7500\,{\rm{g}}\) of sand from the beach. Total how many kilograms of sand Vicky has in his sandbox. Ans: Initial sand in the box is \(14,500\,{\rm{g}}\,{\rm{ = }}\,\frac{{14,500}}{{1000}}\,{\rm{kg}}\, = \,14.\,5\,{\rm{kg}}\) The sand bough from the beach \( = 7500\,{\rm{g}}\,{\rm{ = }}\,\frac{{7500}}{{1000}}\,{\rm{kg}}\, = \,7.\,5\,{\rm{kg}}\) Total sand in the box \( = 14.5\,{\rm{kg}}\,{\rm{ + }}\,7.5\,{\rm{kg}}\, = \,22\,{\rm{kg}}\)
Q.4. Jessica measures two line segments. The first line segment is \(30\,{\rm{cm}}\) long. The second line segment is \(500\,{\rm{mm}}\) long. How long are the two line segments together? (answer in cm ) Ans: The length of the first line segment \( = \,\,30\,{\rm{cm}}\) The length of the second line segment \({\rm{ = }}\,{\rm{500}}\,{\rm{mm}}\,{\rm{ = }}\,\frac{{500}}{{10}}\,{\rm{cm}}\,{\rm{ = }}\,{\rm{50}}\,{\rm{cm}}\) The total length of two-line segments \( = \,\,30\,{\rm{m}}\,{\rm{ + }}\,{\rm{50}}\,{\rm{m}}\, = \,80\,{\rm{m}}\)
Q.5. The length of the box is \(2\,{\rm{m}}\) and the width is \(40\,{\rm{cm}}\) Find the area of the box in \({\rm{c}}{{\rm{m}}^2}\) Ans: Given the length of the box \(2\,{\rm{m}}\) Width of the box \({\rm{ = }}\,{\rm{40}}\,{\rm{cm}}\) Area of the box \({\rm{ = }}\,{\rm{length}}\, \times \,{\rm{width}}\,{\rm{ = }}\,{\rm{200}}\,\, \times \,40\, = \,8000\,{\rm{c}}{{\rm{m}}^2}\)
In this article, we have discussed various methods of the conversion of units from one unit to another unit. This article also discusses the conversion of metric units and word problems on the conversion of metric units. In this article, we have studied the word problems on the conversion of units of length, weight, area, time and capacity, along with the solved examples that help us solve the numerical problems easily.
Q.1. How do you solve unit conversion problems? Ans: The following steps are to be followed to do unit conversion problems. 1. Read the data and the given units. 2. Now, multiply or divide as required conversion with the conversion factor. 3. Then, solve the problems using the proper formulas and operations.
Q.2. How do you solve metric word problems? Ans: The metric word problems are to be solved by using the unit conversion. Convert any bigger unit to the smaller unit, and we should multiply with the conversion factor. Similarly, to convert any smaller unit to a bigger unit, we should divide it with the conversion factor.
Q.3. Why is unit conversion important? Ans: To solve many real-life problems, unit conversion is very important because we cannot perform basic operations like addition, subtraction, multiplication, division etc., unless the two quantities are in the same units.
Q.4. What are the three basic metric units? Ans: The three basic metric units are metre for length, gram for weight and litre for capacity.
Q.5. What is unit conversion? Ans: Conversion of units is a multi-step process that involves multiplication or division by a numerical factor.
Learn about Measurement here
We hope you find this article on ‘Word Problems on Conversion of Units ‘ helpful. In case of any queries, you can reach back to us in the comments section, and we will try to solve them.
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Standard 6.3.3.
Solve problems in various contexts involving conversion of weights, capacities, geometric measurements and times within measurement systems using appropriate units.
Estimate weights, capacities and geometric measurements using benchmarks in measurement systems with appropriate units.
For example : Estimate the height of a house by comparing to a 6-foot man standing nearby.
Big Ideas and Essential Understandings
Standard 6.3.3 Essential Understandings
Students have years of diverse experiences with measurement from prior classroom instruction and from using measurement in their everyday lives. These formal and informal experiences become the building blocks for students to estimate measurements and choose appropriate size and units of measurement for various situations.
Understanding the relationships among units within a measurement system is essential for students to use ratios to convert from one unit to another in solving problems. Students at this level use ratio and reasoning about multiplication and division to convert units within measurement systems and solve real-world and mathematical problems. This standard starts the learning progression of algebra concepts that moves students from ratios to proportions to functions, as well as the use of algebra in geometry.
6.3.3 Converting and Estimating Measurements
6.3.3.1 Solve problems in various contexts involving conversion of weights, capacities, geometric measurements and times within measurement systems using appropriate units.
6.3.3.2 Estimate weights, capacities and geometric measurements using benchmarks in measurement systems with appropriate units.
What students should know and be able to do [at a mastery level] related to these benchmarks:
Work from previous grades that supports this new learning includes:
NCTM Standards
Common Core State Standards (CCSS)
Ms. Rykken's students were excited about the recent CO 2 car competition in their industrial technology class, where they raced the cars they had designed and built. She decides to use this opportunity for them to use their own data and to review working with rates and unit conversion.
She began the class by asking for the velocity of the winning car. Students could only respond with the winning time (0.971 seconds).
Teacher: How is the velocity of real cars expressed?
Student: Speedometers tell us how many miles per hour we're going.
Teacher: That sounds like a relationship between distance and time. What is the relationship between distance and time for the winning CO 2 car?
Student: Well, the track was 66 feet long and it took the car 0.971 seconds to travel that distance.
Teacher: So the winning car traveled 66 feet in 0.971 seconds. We can write that relationship as a ratio, or fraction $\frac{66\ feet}{0.971\ seconds}$ . But you said that real cars express velocity as miles per hour. How can we convert feet per second to miles per hour?
Student : The feet need to be changed to miles, and the seconds need to be changed to hours.
Teacher: Yes, but how do we do that?
Student: I know how to change the time. There are 60 seconds in every minute, and 60 minutes in every hour. We can just multiply.
Teacher: Tell me more.
Student : If I multiply $\frac{66\ feet}{0.971\ seconds}\times \frac{60\ seconds}{1\ minute}\times \frac{60\ minutes}{1\ hour}$, I'll know how many feet the car went in 1 hour.
Teacher: How do we know that multiplying by those fractions didn't change the original velocity?
Student: Because each of the fractions is equivalent to 1, and multiplying by 1 gives you the same value.
Teacher: Since the fractions are equivalent to 1, could I have inverted them and gotten the same result from multiplying?
Student: No, that would mess up the units. The fractions need to be set up so that the units cancel, like seconds with seconds and minutes with minutes. After multiplying, you're left with $\frac{237,600\ feet}{0.971\ hour}$.
Teacher: That makes sense. Now we've converted the time, but we're not finished. For real cars, we express velocity in miles per hour. How do we convert the feet to miles?
Student: The same way. We multiply using the relationship that every mile has 5,280 feet.
Teacher: Do I multiply by $\frac{5,280\ feet}{1\ mile}$ or $\frac{1\ mile}{5,280\ feet}$?
Student: If you want the feet to cancel, you'll need to use $\frac{1\ mile}{5,280\ feet}$ .
Teacher: Like this? $\frac{237,600\ feet}{0.971\ hour}\times \frac{1\ mile}{5,280\ feet}$?
Student: Yes.
Teacher: What is the result?
Student: About 46.3 miles per hour.
Teacher: WOW! That's amazing! It's a good think you didn't race your cars outside the school, because the speed limit there is 30 miles per hour.
Student: Could we have changed the feet to miles first and gotten the same answer?
Teacher: Good question. Does it change the result if we multiply in a different order?
Student: No, multiplication is commutative, which means that the order doesn't matter.
Teacher: Yes, that's right.
Student: I did all those steps at the same time and got the same result.
Teacher: Like this: $\frac{66\ feet}{0.971\ seconds}\times \frac{60\ seconds}{1\ minute}\times \frac{60\ minutes}{1\ hour}\times\frac{1\ mile}{5,280\ feet} $? Excellent! That's very efficient. Now I'd like each of you to find the velocity of your CO 2 car in miles per hour.
Ms. Rykken circulates the room to assist students and hear tales of their race experiences.
Teacher Notes
Weighing Your Car
This lesson asks students to measure the area of a car tire's footprint and its air pressure in order to estimate the car's weight.
Have You Ever Seen a Tree Big Enough to Drive a Car Through?
This challenge allows students explore how foresters use measurement.
Information |Description= Henry Cowell Redwoods State Park, Redwood Grove. Man standing beside a particularly large Coastal Redwood tree. |Source= Created this image on Honeymoon in Santa Cruz, CA |Date= October, 2006 |Author= Larry McElhiney |Permiss)
Does Polygon Need a Jacket?
This challenge asks students to estimate the temperature in Fahrenheit given Celsius.
Additional Instructional Resources
Learning Measurement Through Practice
This article describes a team-taught activity-based format to teach students about measurement.
New Vocabulary
capacity: measure of how much a container can hold. Units of capacity are special types of volume units used for containers whose length, width, and height cannot be measured. Capacity is usually used for things such as liquids or pourable substances, such as grains of sugar.
Example: The capacity of a soda pop can is 12 fluid ounces or 355 milliliters.
customary system: measurement system used most often in the United States.
length: inch, foot, yard, and mile
weight : ounce, pound, and ton
capacity : cup, pint, quart, and gallon
temperature : degrees Fahrenheit
metric system: measurement system used in most countries around the world based on the base-ten numeration system.
length: millimeter, centimeter, meter, and kilometer
weight: gram and kilogram
capacity: milliliter and liter
temperature: degrees Celsius
metric system prefixes: kilo means 1000, hecto means 100, deka means 10, deci means $\frac{1}{10}$, centi means $\frac{1}{100}$, and milli means $\frac{1}{1000}$.
weight: measure of how heavy something is.
Example : The weight of a bag of sugar may be 4 pounds or 1.8 kilograms.
Reflection - Critical Questions regarding the teaching and learning of these benchmarks
(DOK: Level 1)
1. Last week, Harry walked his dog 4 days at a nearby park. Each day they walked on a trail 2,400 meters long. How many kilometers did they walk at the park last week?
a. 9,600 kilometers b. 960 kilometers
c. 96 kilometers d. 9.6 kilometers
(DOK: Level 2)
2. The pilot of a passenger jet announced that their cruising altitude was approximately 31,750 feet. About how many miles above the ground is the plane? Explain your reasoning.
Answer: The plane is about 6 miles above the ground. There are 5,280 feet in one mile, so I divided 31,750 by 5,280 to find the number of miles in 31,750 feet. The answer is a little more than 6.
3. A delivery truck brought several bags of concrete mix to a home improvement store. In all, 10.8 tons of concrete mix were delivered. If each bag of concrete mix weighed 60 pounds, about how many bags did the truck deliver?
a. 556 bags b. 360 bags
c. 270 bags d. 180 bags
(DOK: Level 3)
Answer: 200 m or 0.2 km
5. Figure out which number goes in which place, using reasonable estimates.
A man weighs _____ kg. This is _____ times the amount he weighed at birth.
He drives his car _____ miles in one hour. This is _____ times the distance he walks in one hour. 15 22 60 88
Possible answer: 88, 22, 60, 15
(DOK Level 4)
6. Mike uses a pedometer to keep track of how many steps he takes each day. He plans to hike 8 miles next Saturday. Predict how many steps Mike's pedometer will show from hiking 8 miles. Explain your reasoning.
Struggling Learners
Example:
Examples:
This challenge requires students compare rates between customary and metric measurement systems.
The video on this site will help students convert between measurement systems.
Administrative/Peer Classroom Observation
(descriptive list) | (descriptive list) |
selecting reasonable units of measure, deciding on appropriate tools and measuring actual objects, including irregular shapes and objects. | using the real world as a source of opportunities for measurement investigations that require multiple decisions. |
using commonly understood benchmarks to estimate measurements, then testing their predictions for reasonableness when possible. | asking students to compare estimated and actual measurements to develop a sense of reasonableness. |
understanding that measurements are approximate and that units are chosen based on the degree of accuracy needed and tools available for measurement. | giving students experiences in judging what degree of accuracy is required in a given situation and whether an overestimate or underestimate is more desirable. |
generalizing measurement techniques and strategies to develop formulas. | providing experiences for exploration and discovery of formulas rather than providing formulas and asking for rote memorization; helping students recognize formulas as efficient ways to count repeated units. |
making connections between units of length, area and volume. | emphasizing how length and width are combine to form the square units of area; and how length, width, and height are combined to form the cubic units of volume. |
using ratios and reasoning strategies to solve problems involving conversion of units within measurement systems. | proposing problems that require students to use ratios and reasoning strategies in converting units within measurement systems. |
using approximate "rules of thumb" to convert units between measurement systems. | asking students to make approximations in the metric system based on customary measurement and vice-versa. |
connecting measurement to other mathematical areas. | explicitly connecting measurement to number, geometry, algebra and data analysis. |
connecting measurement to other content areas. | collaborating with colleagues to integrate content and support students in making connections. |
using measurement concepts and skills to solve real-world problems and extending their learning to new situations. | requiring a dynamic interaction between students and their environment, so that students encounter measurement outside of school, as well as inside. |
communicating mathematical thinking to others; analyzing others' mathematical thinking and strategies. | selecting students with different approaches to share thinking with the class. |
Parent Resources
Using Metric Conversions to Solve Problems
Learning Objective(s)
· Solve application problems involving metric units of length, mass, and volume.
Introduction
Learning how to solve real-world problems using metric conversions is as important as learning how to do the conversions themselves. Mathematicians, scientists, nurses, and even athletes are often confronted with situations where they are presented with information using metric measurements, and must then make informed decisions based on that data.
To solve these problems effectively, you need to understand the context of a problem, perform conversions, and then check the reasonableness of your answer. Do all three of these steps and you will succeed in whatever measurement system you find yourself using.
Understanding Context and Performing Conversions
The first step in solving any real-world problem is to understand its context. This will help you figure out what kinds of solutions are reasonable (and the problem itself may give you clues about what types of conversions are necessary). Here is an example.
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Problem |
| |
| 10,000 5,000 1,500 800 400 200
18,000 | To figure out how many kilometers he would run, you need to first add all of the lengths of the races together and convert that measurement to kilometers.
|
|
| Use the factor label method and unit fractions to convert from meters to kilometers. |
|
| Cancel, multiply, and solve. |
| The runner would run 18 kilometers. |
|
This may not be likely to happen (a runner would have to be quite an athlete to compete in all of these races) but it is an interesting question to consider. The problem required you to find the total distance that the runner would run (in kilometers). The example showed how to add the distances, in meters, and then convert that number to kilometers.
An example with a different context, but still requiring conversions, is shown below.
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Problem |
| |
| 295 dl = ___ l 28,000 ml = ___ l | The two measurements are in different units. You can convert both units to liters and then compare them. |
|
| Convert dl to liters. |
|
| Cancel similar units and multiply.
295 dl = 29.5 liters. |
|
| Convert ml to liters.
28,000 ml = 28 liters |
| 29.5 liters – 28 liters = 1.5 liters | The question asks for “difference in capacity” between the bottles. |
| There is a difference in capacity of 1.5 liters between the two bottles. |
This problem asked for the difference between two quantities. The easiest way to find this is to convert one quantity so that both quantities are measured in the same unit, and then subtract one from the other.
One boxer weighs in at 85 kg. He is 80 dag heavier than his opponent. How much does his opponent weigh?
A) 5 kg
B) 84.2 kg
C) 84.92 kg
D) 85.8 kg
Incorrect. Look at the unit labels—the boxer is 80 heavier, not 80 heavier. The correct answer is 84.2 kg.
B) 84.2 kg Correct. 80 dag = 0.8 kg, and 85 – 0.8 = 84.2.
C) 84.92 kg Incorrect. This would have been true if the difference in weight was 8 dag, not 80 dag. The correct answer is 84.2 kg.
D) 85.8 kg Incorrect. The first boxer is 80 dag , not than his opponent. This question asks for the opponent’s weight. The correct answer is 84.2 kg.
|
Checking your Conversions
Sometimes it is a good idea to check your conversions using a second method. This usually helps you catch any errors that you may make, such as using the wrong unit fractions or moving the decimal point the wrong way.
| ||
Problem |
| |
| 87 cl + 4.1 dl + ___ = 2 l | You are looking for the amount of liquid needed to fill the bottle. Convert both measurements to liters and then solve the problem. |
| 87 cl = ___ l
| Convert 87 cl to liters. |
| 4.1 dl = ___ l
| Convert 4.1 dl to liters. |
| 87 cl + 4.1 dl + ___ = 2 l
0.87 liter + 0.41 liter + ___ = 2 liters
2 liters – 0.87 liter – 0.41 liter = 0.72 liter | Subtract to find how much more liquid is needed to fill the bottle. |
| The amount of liquid needed to fill the bottle is 0.72 liter. |
Having come up with the answer, you could also check your conversions using the quicker “move the decimal” method, shown below.
| ||
Problem |
| |
| 87 cl + 4.1 dl + ___ = 2 l | You are looking for the amount of liquid needed to fill the bottle. |
| 87 cl = ___ l
| Convert 87 cl to liters.
On the chart, l is two places to the left of cl.
Move the decimal point two places to the left in 87 cl. |
| 4.1 dl = ___ l
| Convert 4.1 dl to liters.
On the chart, l is one place to the left of dl.
Move the decimal point one place to the left in 4.1 dl. |
| 87 cl + 4.1 dl + ___ = 2 l
0.87 liter + 0.41 liter + ___ = 2 liters
2 liters – 0.87 liter – 0.41 liter = 0.72 liter | Subtract to find how much more liquid is needed to fill the bottle. |
| The amount of liquid needed to fill the bottle is 0.72 liter. |
The initial answer checks out—0.72 liter of liquid is needed to fill the bottle. Checking one conversion with another method is a good practice for catching any errors in scale.
Understanding the context of real-life application problems is important. Look for words within the problem that help you identify what operations are needed, and then apply the correct unit conversions. Checking your final answer by using another conversion method (such as the “move the decimal” method, if you have used the factor label method to solve the problem) can cut down on errors in your calculations.
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One application of rational expressions deals with converting units. Units of measure can be converted by multiplying several fractions together in a process known as dimensional analysis.
The trick is to decide what fractions to multiply. If an expression is multiplied by 1, its value does not change. The number 1 can be written as a fraction in many different ways, so long as the numerator and denominator are identical in value. Note that the numerator and denominator need not be identical in appearance, but rather only identical in value. Below are several fractions, each equal to 1, where the numerator and the denominator are identical in value. This is why, when doing dimensional analysis, it is very important to use units in the setup of the problem, so as to ensure that the conversion factor is set up correctly.
Example 1.6.1
If 1 pound = 16 ounces, how many pounds are in 435 ounces?
[latex]\begin{array}{rrll} 435\text{ oz}&=&435\text{ \cancel{oz}}\times \dfrac{1\text{ lb}}{16\text{ \cancel{oz}}} \hspace{0.2in}& \text{This operation cancels the oz and leaves the lbs} \\ \\ &=&\dfrac{435\text{ lb}}{16} \hspace{0.2in}& \text{Which reduces to } \\ \\ &=&27\dfrac{3}{16}\text{ lb} \hspace{0.2in}& \text{Solution} \end{array}[/latex]
The same process can be used to convert problems with several units in them. Consider the following example.
Example 1.6.2
A student averaged 45 miles per hour on a trip. What was the student’s speed in feet per second?
[latex]\begin{array}{rrll} 45 \text{ mi/h}&=&\dfrac{\text{45 \cancel{mi}}}{\text{\cancel{hr}}}\times \dfrac{5280 \text{ ft}}{1\text{ \cancel{mi}}}\times \dfrac{1\text{ \cancel{hr}}}{3600\text{ s}}\hspace{0.2in}&\text{This will cancel the miles and hours} \\ \\ &=&45\times \dfrac{5280}{1}\times \dfrac{1}{3600} \text{ ft/s}\hspace{0.2in}&\text{This reduces to} \\ \\ &=&66\text{ ft/s}\hspace{0.2in}&\text{Solution} \end{array}[/latex]
Example 1.6.3
Convert 8 ft 3 to yd 3 .
[latex]\begin{array}{rrll} 8\text{ ft}^3&=&8\text{ ft}^3 \times \dfrac{(1\text{ yd})^3}{(3\text{ ft})^3}&\text{Cube the parentheses} \\ \\ &=&8\text{ }\cancel{\text{ft}^3}\times \dfrac{1\text{ yd}^3}{27\text{ }\cancel{\text{ft}^3}}&\text{This will cancel the ft}^3\text{ and replace them with yd}^3 \\ \\ &=&8\times \dfrac{1\text{ yd}^3}{27}&\text{Which reduces to} \\ \\ &=&\dfrac{8}{27}\text{ yd}^3\text{ or }0.296\text{ yd}^3&\text{Solution} \end{array}[/latex]
Example 1.6.4
A room is 10 ft by 12 ft. How many square yards are in the room? The area of the room is 120 ft 2 (area = length × width).
Converting the area yields:
[latex]\begin{array}{rrll} 120\text{ ft}^2&=&120\text{ }\cancel{\text{ft}^2}\times \dfrac{(1\text{ yd})^2}{(3\text{ }\cancel{\text{ft}})^2}&\text{Cancel ft}^2\text{ and replace with yd}^2 \\ \\ &=&\dfrac{120\text{ yd}^2}{9}&\text{This reduces to} \\ \\ &=&13\dfrac{1}{3}\text{ yd}^2&\text{Solution} \\ \\ \end{array}[/latex]
The process of dimensional analysis can be used to convert other types of units as well. Once relationships that represent the same value have been identified, a conversion factor can be determined.
Example 1.6.5
A child is prescribed a dosage of 12 mg of a certain drug per day and is allowed to refill his prescription twice. If there are 60 tablets in a prescription, and each tablet has 4 mg, how many doses are in the 3 prescriptions (original + 2 refills)?
[latex]\begin{array}{rrll} 3\text{ prescriptions}&=&3\text{ \cancel{pres.}}\times \dfrac{60\text{ \cancel{tablets}}}{1\text{ \cancel{pres.}}}\times \dfrac{4\text{ \cancel{mg}}}{1\text{ \cancel{tablet}}}\times \dfrac{1\text{ dosage}}{12\text{ \cancel{mg}}}&\text{This cancels all unwanted units} \\ \\ &=&\dfrac{3\times 60\times 4\times 1}{1\times 1\times 12}\text{ or }\dfrac{720}{12}\text{ dosages}&\text{Which reduces to} \\ \\ &=&60\text{ daily dosages}&\text{Solution} \\ \\ \end{array}[/latex]
\[\begin{array}{rrlrrl} 12\text{ in}&=&1\text{ ft}\hspace{1in}&10\text{ mm}&=&1\text{ cm} \\ 3\text{ ft}&=&1\text{ yd}&100\text{ cm}&=&1\text{ m} \\ 1760\text{ yds}&=&1\text{ mi}&1000\text{ m}&=&1\text{ km} \\ 5280\text{ ft}&=&1\text{ mi}&&& \end{array}\]
Imperial to metric conversions:
\[\begin{array}{rrl} 1\text{ inch}&=&2.54\text{ cm} \\ 1\text{ ft}&=&0.3048\text{ m} \\ 1\text{ mile}&=&1.61\text{ km} \end{array}\]
\[\begin{array}{rrlrrl} 144\text{ in}^2&=&1\text{ ft}^2\hspace{1in}&10,000\text{ cm}^2&=&1\text{ m}^2 \\ 43,560\text{ ft}^2&=&1\text{ acre}&10,000\text{ m}^2&=&1\text{ hectare} \\ 640\text{ acres}&=&1\text{ mi}^2&100\text{ hectares}&=&1\text{ km}^2 \end{array}\]
\[\begin{array}{rrl} 1\text{ in}^2&=&6.45\text{ cm}^2 \\ 1\text{ ft}^2&=&0.092903\text{ m}^2 \\ 1\text{ mi}^2&=&2.59\text{ km}^2 \end{array}\]
\[\begin{array}{rrlrrl} 57.75\text{ in}^3&=&1\text{ qt}\hspace{1in}&1\text{ cm}^3&=&1\text{ ml} \\ 4\text{ qt}&=&1\text{ gal}&1000\text{ ml}&=&1\text{ litre} \\ 42\text{ gal (petroleum)}&=&1\text{ barrel}&1000\text{ litres}&=&1\text{ m}^3 \end{array}\]
\[\begin{array}{rrl} 16.39\text{ cm}^3&=&1\text{ in}^3 \\ 1\text{ ft}^3&=&0.0283168\text{ m}^3 \\ 3.79\text{ litres}&=&1\text{ gal} \end{array}\]
\[\begin{array}{rrlrrl} 437.5\text{ grains}&=&1\text{ oz}\hspace{1in}&1000\text{ mg}&=&1\text{ g} \\ 16\text{ oz}&=&1\text{ lb}&1000\text{ g}&=&1\text{ kg} \\ 2000\text{ lb}&=&1\text{ short ton}&1000\text{ kg}&=&1\text{ metric ton} \end{array}\]
\[\begin{array}{rrl} 453\text{ g}&=&1\text{ lb} \\ 2.2\text{ lb}&=&1\text{ kg} \end{array}\]
Fahrenheit to Celsius conversions:
\[\begin{array}{rrl} ^{\circ}\text{C} &= &\dfrac{5}{9} (^{\circ}\text{F} – 32) \\ \\ ^{\circ}\text{F}& =& \dfrac{9}{5}(^{\circ}\text{C} + 32) \end{array}\]
For questions 1 to 18, use dimensional analysis to perform the indicated conversions.
For questions 19 to 27, solve each conversion word problem.
Answer Key 1.6
Celsius to Fahrenheit conversion scale long description: Scale showing conversions between Celsius and Fahrenheit. The following table summarizes the data:
Celsius | Fahrenheit |
---|---|
−40°C | −40°F |
−30°C | −22°F |
−20°C | −4°F |
−10°C | 14°F |
0°C | 32°F |
10°C | 50°F |
20°C | 68°F |
30°C | 86°F |
40°C | 104°F |
50°C | 122°F |
60°C | 140°F |
70°C | 158°F |
80°C | 176°F |
90°C | 194°F |
100°C | 212°F |
[Return to Celsius to Fahrenheit conversion scale]
Intermediate Algebra (Convert to MathJax) Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License , except where otherwise noted.
IMAGES
COMMENTS
Solving Problems Involving Conversion of Units; After going through this module, you are expected to: 1. convert metric unit to another metric unit; 2. convert English system unit to another English system unit; 3. convert metric unit to English system unit and vice versa; and. 4. solve problems involving conversion of units.
1.6 Unit Conversion Word Problems. One application of rational expressions deals with converting units. Units of measure can be converted by multiplying several fractions together in a process known as dimensional analysis. The trick is to decide what fractions to multiply. If an expression is multiplied by 1, its value does not change.
Solution. To figure out how many kilometers he would run, you need to first add all of the lengths of the races together and then convert that measurement to kilometers. Use the factor label method and unit fractions to convert from meters to kilometers. Cancel, multiply, and solve. The runner would run 18 kilometers.
Sample Problem 1: Convert 98.35 decameters to centimeters. Solution: Looking at the table of metric units of length, there are three steps to the right, from decameters to centimeters. This implies that we must move three decimal places to the right to convert 98.35 decameters to centimeters.
Unit test. Our mission is to provide a free, world-class education to anyone, anywhere. Khan Academy is a 501 (c) (3) nonprofit organization. Donate or volunteer today! "Module 2 focuses on length, mass, and capacity in the metric system where place value serves as a natural guide for moving between larger and smaller units."
1. Compare the two units. 2. Find the conversion factors that gives the appropriate ratio to the given unit. 3. Write the conversion as a fraction, where the denominator is in the same unit as the given unit. 4. Write a multiplication problem with the original number and the fraction. 5.
Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. ... Convert units word problems (metrics) Convert units multi-step word problems (metric) Math > 5th grade > Converting units of measure > Converting metric units word problems
http://www.greenemath.com/In this video, we practice solving applied problems that involve unit conversions. We work on two unit conversion word problems her...
Unit conversion problems constitute the first week of nearly every science course. Measurement is a basic skill in science, but not all measurement methods are the same. People measure the same thing in different ways and use different units. To communicate between scientists, there has to be a method of converting between the different ...
BIBLIOGRAPHY:BOOKS: • Crisostomo, R. M., & Padua, A. L. (2018). Our World of Math 7 (2nd ed.). Philippines: Vibal Group, Inc.• Orines, F B. et.al. (2017). Gr...
unit and English System unit to another English System unit. • Conversion of Measurement from Metric System unit to English System unit and vice versa • Solving Problems Involving Conversion of Units After going through this module, you are expected to: 1. convert metric unit to another metric unit (M7ME-IIb-1); 2.
Word Problems on Conversion of Units: Conversion of units is a multi-step process that involves multiplication or division by a numerical factor.In Mathematics, while solving numerical problems, it is required to convert the units. Thus the conversion of units should be needed to solve the required calculations wherever it is necessary.
This video is all about solving problems involving the conversion of units of measurement.
Standard 6.3.3. Choose appropriate units of measurement and use ratios to convert within measurement systems to solve real-world and mathematical problems. Solve problems in various contexts involving conversion of weights, capacities, geometric measurements and times within measurement systems using appropriate units.
200. + 100. 18,000. To figure out how many kilometers he would run, you need to first add all of the lengths of the races together and then convert that measurement to kilometers. Use the factor label method and unit fractions to convert from meters to kilometers. Cancel, multiply, and solve. Answer.
Metric units Imperial units Converting units of time Timetables National Curriculum Objectives Mathematics Year 5: (5M4) Solve problems involving converting between units of time Mathematics Year 5: (5M5) Convert between different units of metric measure (for example, kilometre and metre; centimetre and metre; centimetre and millimetre; gram
440 hours. Q4. From the list of people below, who has worked the most amount of hours? A works 8 hour shifts, five times a week. B works 12 hour shifts, three times a week. C works 9 hour shifts, four times a week. D works 6 hour shifts, six times a week. Q5. Anna has been training for a marathon.
1.6 Unit Conversion Word Problems. One application of rational expressions deals with converting units. Units of measure can be converted by multiplying several fractions together in a process known as dimensional analysis. The trick is to decide what fractions to multiply. If an expression is multiplied by 1, its value does not change.
This video covers tutorial of how to solve problem involving conversion of units